Computing and displaying the cubes and the sums of cubes of the first 10 integers in C

#include <stdio.h>
#include <stdlib.h>
#define CUBE(x) ((x)*(x)*(x))
 
int main(void) {
	int i1, running_sum=0;
	i1=1;
	while (i1<=10)
	{       // running_sum=running_sum+CUBE(i1)  
		running_sum+=CUBE(i1);
		printf("%2d  :   cube=  %4d ;   running_sum=  %4d\n", i1, CUBE(i1) , running_sum);
		++i1;
	}
	return 0;
}

#include <stdio.h>

#include <stdlib.h>

#define CUBE(x) ((x)*(x)*(x))

int main(void) {

int i1, running_sum=0;

i1=1;

while (i1<=10)

{ // running_sum=running_sum+CUBE(i1)

running_sum+=CUBE(i1);

printf("%2d : cube= %4d ; running_sum= %4d\n", i1, CUBE(i1) , running_sum);

++i1;

}

return 0;

}

The above program computes and displays cubes and sums of cubes of the first 10 integers. This program also illustrates the use of while loop.
running_sum=running_sum+CUBE(i1)
e.g. for i1=1 the running_sum=0+1=1, for i2=2 the running_sum=1+8=9

The output is:

Computing and displaying cubes and sums of cubes of the first 10 integers in C

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Computing and displaying the cubes and the sums of cubes of the first 10 integers in C